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Mathematics 22 Online
OpenStudy (amtran_bus):

Expand this log! I give medals!

OpenStudy (amtran_bus):

OpenStudy (amtran_bus):

Ok, actually natural log :)

OpenStudy (amtran_bus):

@ganeshie8

OpenStudy (amtran_bus):

I know division - subtraction.

OpenStudy (anonymous):

so the first thing you'll wanna do is apply the 'quotient rule'

OpenStudy (amtran_bus):

ln 2x^6-(x+3)^10 ?

OpenStudy (amtran_bus):

I ment -ln (x+3)^10.

OpenStudy (anonymous):

like this? ln 2x^6 - ln (x+3)^10

OpenStudy (amtran_bus):

I think so.

OpenStudy (anonymous):

yaya, you did that rule right. so lets take care of the powers of 6 and 10 by applying the 'power reduction rule'

OpenStudy (amtran_bus):

bring it in front of ln?

OpenStudy (anonymous):

ya, post up what you get

OpenStudy (amtran_bus):

2 ln 6 - 10 ln (x+3)

OpenStudy (anonymous):

ln 2x^6 - ln (x+3)^10 dont forget the x with the 2, and the 6 goes infront 6 ln 2x - 10 ln (x+3)

OpenStudy (amtran_bus):

Thanks, I knew that, just goofed.

OpenStudy (anonymous):

yep! we can expand it a bit more still, do you see that we can factor out a 2 from the 6 and the 10 coefficeitns?

OpenStudy (amtran_bus):

Yes

OpenStudy (anonymous):

ln 2x^6 - ln (x+3)^10 6 ln 2x - 10 ln (x+3) 2 (3 ln 2x - 5 ln(x+3))

OpenStudy (amtran_bus):

Is that it?

OpenStudy (anonymous):

ya, i believe so, lemme double check...

OpenStudy (amtran_bus):

Sure

OpenStudy (anonymous):

ya, thats it ^_^

OpenStudy (amtran_bus):

Thanks and God bless!

OpenStudy (anonymous):

actually, we can use the product rule..

OpenStudy (anonymous):

sorry, i just realized that

OpenStudy (anonymous):

so the ln 2x can have the product rule applied to it sorry i over looked that!

OpenStudy (amtran_bus):

Can you show me what you mean? It's fine!

OpenStudy (anonymous):

2 (3 ln 2x - 5 ln(x+3)) looking only at ln(2x) is the same as ln((2)x) so 2 times x, now apply the product rule: ln(2) + ln(x) re insert this back in: 2 ( 3(ln 2 + ln x) - 5 ln(x+3) )

OpenStudy (anonymous):

k, now we are done ^_^ haha

OpenStudy (amtran_bus):

I'm sure your right, but it won't take it. Maybe my input error?

OpenStudy (anonymous):

does it need to be "ln(2) + ln(x)" ?

OpenStudy (anonymous):

and does it need to be "(5)ln(x+3)" ?

OpenStudy (amtran_bus):

Like this?

OpenStudy (anonymous):

u have this right now: 3(3ln(2) + ln(x)) - (5)ln(x+3) do it like this: 3(3(ln(2) + ln(x)) - (5)ln(x+3)) do you see what u were missing? a "(" and a ")"

OpenStudy (amtran_bus):

Still says wrong :(

OpenStudy (amtran_bus):

I can ask my my teacher. Thanks !

OpenStudy (anonymous):

hmm....

OpenStudy (anonymous):

oh, haha, i found it: we kept putting in 3(3(ln(2) + ln(x)) - (5)ln(x+3)) but it should be: 2( 3( ln(2) + ln(x) ) - (5)ln(x+3) ) some how we got a 3 out infront, but it should be a 2.

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