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Mathematics 12 Online
OpenStudy (anonymous):

Need help solving these problems. I know it is A = P(e)^rt I did that with the problems and keep getting the wrong answers.

OpenStudy (anonymous):

OpenStudy (kc_kennylau):

Remember, the 12% is per year

OpenStudy (anonymous):

yeah so the ^(.12)(20) right?

OpenStudy (kc_kennylau):

well, \(e\) is for continuous, so this case don' t use \(e\) :)

OpenStudy (kc_kennylau):

A=P(1+r)^t

OpenStudy (anonymous):

so the last problem I tried would be 2000/1.2^20?

OpenStudy (kc_kennylau):

Well, it's compounded monthly, so the formula would be \(A=$2000(1+\frac{12\%}{12})^t\), where \(t\) is the number of months

OpenStudy (kc_kennylau):

And he's not asking you for the interest, so don't subtract \($2000\) :)

OpenStudy (kc_kennylau):

OK, let me do part b for you, and see if you can do the rest by yourself :)

OpenStudy (kc_kennylau):

Principal after 6 months \(=$2000(1+\frac{12\%}{12})^6\) \(\approx$2123.04\) (correct to the nearest cent)

OpenStudy (anonymous):

why over 12? becuase that how many years in a month? and what if the time was years instead of months for the exponent?

OpenStudy (anonymous):

or just convert the months to years right?

OpenStudy (kc_kennylau):

Then you'll have to multiply the number of years by \(12\) :)

OpenStudy (kc_kennylau):

no years to months

OpenStudy (anonymous):

years to months*

OpenStudy (kc_kennylau):

lol

OpenStudy (anonymous):

ok and the 12% was over 12 becuase 12 is number of years in months right

OpenStudy (kc_kennylau):

Because the 12% is per year and its compounded monthly :)

OpenStudy (kc_kennylau):

Are you all right? :)

OpenStudy (anonymous):

lol yea trying to workem out

OpenStudy (kc_kennylau):

what've u got?

OpenStudy (anonymous):

2000*0.04^240 for last one

OpenStudy (anonymous):

for last one just trying to do the power

OpenStudy (kc_kennylau):

it's not 0.04, it's still \((1+\frac{12\%}{12})\) which is \(1.01\)

OpenStudy (anonymous):

yea, idk why or how i got mine but redid it an got that. just trying to do that to the power of 240

OpenStudy (kc_kennylau):

use google search as a calculator

OpenStudy (kc_kennylau):

or Wolfram|Alpha

OpenStudy (anonymous):

i get $21875.10 for last one

OpenStudy (anonymous):

21785.11*

OpenStudy (anonymous):

what if the world problem says year compounded semiannually

OpenStudy (kc_kennylau):

sorry was browsing

OpenStudy (kc_kennylau):

then the formula would be \($2000(1+\frac{12\%}2)^t\), where \(t\) is the number of half-year

OpenStudy (anonymous):

so 3 years would be 1.5

OpenStudy (kc_kennylau):

6

OpenStudy (anonymous):

oh thought you ment by half years like litterlaly half

OpenStudy (kc_kennylau):

yep :)

OpenStudy (kc_kennylau):

General formula: \(A=P\times(1+\frac{r}{y})^{yt}\), where \(r\) is the interest per annum, \(y\) is the number of times compounded in a year, \(t\) is the number of years. (Don't google this as the symbols are created by me)

OpenStudy (anonymous):

Ah I got those 6, but trying the foumals with these one I get it wrong the first one I did 1600( 1 + 4.25/2 )^6

OpenStudy (anonymous):

OpenStudy (kc_kennylau):

sorry for late reply

OpenStudy (kc_kennylau):

it's \(r\%\) that is \(4\frac14\%\)

OpenStudy (kc_kennylau):

and read the question carefully, the second question is asking the reverse

OpenStudy (anonymous):

4 1/4 is 4.25 right?

OpenStudy (kc_kennylau):

yep :)

OpenStudy (anonymous):

So my calculation above was right?

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