Question

Volume of H2O 200.0 mL H2O
Mass of NaOH 2.535 g NaOH
Initial temperature in calorimeter 24.2 °C
Final temperature in calorimeter 27.8 °C
Calculate the amount of energy involved in this dissolving process.

Answer 1

q = m c (T2-T1)
200 mL H2O X 1 g/1 mL = 200 g H2O
c = 4.184 J/gC
T2 = 27.8 C
T1 = 24.2 C

Heat gained by H2O = 200 g X 4.18 J/gC X (27.8 - 24.2) = 3010 J