A space shuttle in outer space moves with speed 10 m/s. To change its reaction, it accelerates with a constant acceleration of 3m/s^2 at an angle of 30 degrees with respect to its initial velocity for3seconds. Fond the space shuttle's direction of motion and the magnitude of its displacement after 3 seconds.

Question

loser66 · Answer

@DemolisionWolf  prof, help him, please. I want to know, too.

agent0smith · Answer

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break acceleration into components... in x direction: 3cos 30. In y direction: 3sin30

Initial velocity is vx = 10m/s, vy = 0m/s

after time t, the velocity is
vx = 10 + (3cos30)t
vy = (3sin30)t

anonymous · Answer

3m/s^2  for 3 seconds becomes 9m/s in the 30degree direction.
we then add the vectors of the velocities to get the direction
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loser66 · Answer

@agent0smith  how can we add acceleration with velocity like that?

anonymous · Answer

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