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Suppose a solution was too concentrated for an accurate reading with the spectrophotometer. the concentrated solution was diluted by placing 1.00 ml of the concentrated solution of 4.00ml of water. The solution was then placed in the spectrophotometer, an absorbance was obtained, and after a few calculations the molar concentration was calculated to be 3.5 x 10^6 M. What was the concentration of the original stock solution before dilution?
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well it is a tricky question... math doesn't work here... the initial conc. of the solution will be 1.75*10^7 M.
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