Crystal Field Theory (high spin and low spin) can help me clarify??
|dw:1385015444836:dw|
i am having a hunch that it must be related to Cr3+ being d3, does anyone knows why this anomally happens??
CN\(^-\) is a strong field ligand, therefore it would generate a higher field splitting as compared to Cl\(^-\).
@abb0t yup CN- is a strong field ligand, thus is should be low spin right? I understood that d3 cannot have both high and low spins, therefore it depends on the ligands. But i dont understand why CrCN6]3- is high spin
this is the answer sheet, i dont understand why a strong ligad should have a high spin
|dw:1385030588418:dw|
where did u get that information? any link?
This is due to sigma/ pi- bonding properties. This can best be expained using molecular orbital theory. Look at the M.O diagram for cyanide and look particularly at it's antibonding
@abb0t there is indeed a pair of ellectrons in one of the sigma* bond in CN-, what does that implicate? that it will produce a high spin?
This makes the complex, low-spin, meaning splitting energy is large. Also, look at d\(^n\) count. There are quite a bit of things to take into account here when you're looking at this, but yu can always use crystal field theory and MO to explain this. It's a tough concept to explain. I myself do not even know it well. Just from what I was taught in class.
And this was about a year or so ago.
yeah that was what was thought to us to, but the answer sheet provided contradicts.. maybe they just made a mistake then! thank you!(:
Join our real-time social learning platform and learn together with your friends!