When you're given the side lengths and/or angle measures of a triangle, how do you know if it is: (a. able to actually exist (b. one or two triangles ?
As far as side lengths if the longest side is less than the sum of the other two sides the triangle can exist. Here's a triangle tester: http://1728.org/trianinq.htm
Do you know how I can determine a triangle based on trig functions? Like, in my notes it says that when adjacent>opposite>hypotenuse, there are two triangles, but I don't quite understand it.
@sunny9dragon Are you talking about the SSA, as known as the "Ambiguous Case?" That is the one where you are given two sides and a non-included angle of a possible triangle. Zero, one, or two different triangles may exist based on the data.
Does the Ambiguous case only apply to SSA?
To my knowledge, the Ambiguous Case is based on SSA. Read more here: http://www.regentsprep.org/regents/math/algtrig/ATT12/lawofsinesAmbiguous.htm
Just use the law of sines. It's a ratio system such that sin(angleA)/side a is equal to all other sides in the same way ie... = sin(angleB)/side b = sin(angle C)/ side c. Where the side is across from the angle. This is true of all triangles, not just ones with 90deg angles. If it had a 90deg angle, this would be a lot easier...
Oh, okay, that makes more sense. How can I tell if a triangle has no solutions or only one solution?
Oh okay, @thenateman27 .. Is the law of cosines useful in this?
@sunny9dragon Please post the actual problem and then we will know how to proceed. Thanks.
The given measurements may or may not determine a triangle. C=37 degrees, a=18, c=9
And I'm supposed to decide whether it is a triangle, an ambiguous case, or not a triangle.
So; sin(37)/9 = sin(A)/18 cross multiply, and simple algebra will give you angle A.
If you're results make sense, then it should work out, but that result makes no sense.
I have a question about another triangle. In the triangle that I will attach shortly after sending this, is it true that this triangle cannot be solved with the law of sines?
That triangle is impossible, yes.
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