Question

A doctor’s office schedules 10-minute and 20-minute appointments. The doctor also makes hospital rounds for four hours each weekday.


a. Suppose the doctor limits these activities to, at most, 30 hours per week. Write an inequality to represent the number of each type of office visit she may have in a week. Let x represent the number of 10-minute appointments and y the number of 20-minute appointments.
b. Graph the inequality.
c. Is (63, 30) a solution of the inequality?

Answer 1

I am attaching a graph as we speak.

Answer 2

and @BigTeach2345 I more than appreciate the help im about to receive.

Answer 3

well write out everthing we know.
we know that 10x is the number of minutes used for 10min appt. a week
we know that 20y is the amount of minutes used for 20 min appt. a week
we know that he uses 4 hours a day for rotations or 240min a day 5 days a week or 1200min
for no more then 30 hours a week or 1800 minutes
how do you set this up into a equation

Answer 4

Where is the 4 hours of rounds included?

Answer 5

10x+20y\[\le \]600

Answer 6

yes that looks great!

Answer 7

now how do you do part c

Answer 8

i honestly have no idea, uhm..

Answer 9

you have two ways to procide you could use the graph or use the formula.

Answer 10

is it c?

Answer 11

c has you try a point and see if it is working your second graph it great you just have to see if your point falls in that graph.

Answer 12

thank you for your help!

Answer 13

@krollhai Do the 4 hour rounds that are made need to be included?
Because I was thinking that the initial equation would be 10x + 20y ≦ (30 - (4*5))*60.
That should remove the 4 hour rounds for the week from the equation, and leave only the time spent on x or y.