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Calculus1 7 Online
OpenStudy (anonymous):

Hi everyone! Can someone please confirm an algebra mistake for me? I attached a picture of the work. Shouldn't it be "m" on the bottom and not "2m"? Thanks!

OpenStudy (anonymous):

OpenStudy (kc_kennylau):

It was \(\dfrac12M+m\) now it's \(\dfrac12(M+2m)\)

OpenStudy (anonymous):

are you asking me or telling me?

OpenStudy (kc_kennylau):

I'm telling you that it's correct

OpenStudy (anonymous):

can you please show me how they got 2m on the bottom? can't figure it out

OpenStudy (anonymous):

wait...are you telling me the 2m is correct or m is correct?

OpenStudy (kc_kennylau):

\[\left[\frac12MR^2+mR^2\right]\omega=mv_id\]\[\frac12\left[MR^2+2mR^2\right]\omega=mv_id\]\[\omega=\frac{mv_id}{\frac12(MR^2+2mR^2)}=\frac{2mv_id}{MR^2+2mR^2}=\frac{2mv_id}{(M+2m)R^2}\]

OpenStudy (anonymous):

haha...yikes! thanks a bunch! I see it now! :o)

OpenStudy (kc_kennylau):

no problem :)

OpenStudy (anonymous):

one question...

OpenStudy (anonymous):

if you factor out a fraction from a coefficient of 1, it's like 1 divided by (1/2) which equals 2 right?

OpenStudy (kc_kennylau):

yep

OpenStudy (anonymous):

wow...you don't see that everyday...it can sneak up on you! thanks again!

OpenStudy (kc_kennylau):

no problem

OpenStudy (phi):

another way to see it \[ \frac{MR^2}{2} + mR^2 \] put the 2nd term over a common denominator, by multiplying by 2/2 \[ \frac{MR^2}{2} + \frac{2mR^2}{2} \\ \frac{MR^2+2mR^2}{2} \]

OpenStudy (anonymous):

thanks phi!

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