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Mathematics
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Horizontal asymptote
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take x^8 common from both denom and num and you will be left with 12/4
\[\large \lim_{x\to\infty}\frac{12x^8-6}{3x^8-2x^7} =\lim_{x\to\infty}\frac{x^8(12-6/x^8)}{x^8(3-2/x)}= \lim_{x\to\infty}\frac{12-6/x^8}{3-2/x} \]
got it? now use the fact that for all n \[\large \lim_{x\to\infty}\frac{K}{x^n}=0 \]
so, the answer would be 4? so it has a horizontal asymptote?
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yes \[\large \lim_{x\to\infty}\frac{12-6/x^8}{3-2/x}=\frac{12-0}{3-0}=4\] so y=4 is a horizontal asymptote
okay thank you! :D
u r welcome
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