Which function below matches the attached graphs?

A. $$f(x)=\sqrt[5]{(x-4)}+2$$

B. $$f(x)=e ^{(x-2)}+3$$

C. $$f(x)=(\frac{ 1 }{ 2 })^x-3$$

D. $$f(x)=\log(x+1)-2$$

Question

Which function below matches the attached graphs?

A. $$f(x)=\sqrt[5]{(x-4)}+2$$

B. $$f(x)=e ^{(x-2)}+3$$

C. $$f(x)=(\frac{ 1 }{ 2 })^x-3$$

D. $$f(x)=\log(x+1)-2$$

anonymous · Answer

attachment

anonymous · Answer

1. D
2. I think is B

anonymous · Answer

number 1 is great number 2 think about what happens when x is very large

anonymous · Answer

3. I think is A

anonymous · Answer

hm, when x is large does it shift to the right? I'm not too sure :o

anonymous · Answer

e is about 2.17 what happens if you raise that to the high power does it level out or get very large?

anonymous · Answer

it would get very large, right?

anonymous · Answer

yes so what graph gets large?

anonymous · Answer

oh, A?

anonymous · Answer

no a levels out for large values of x. Which one grows fast for larger values of x?

anonymous · Answer

C looks like it starts to grow faster for the x values

anonymous · Answer

yes and the farther you move the faster it grows this isa typical power function so I would say 2. is C

anonymous · Answer

so you have 
1. D
2. C
3. A 
4. ?

anonymous · Answer

hehe well for would be B but why would it be B, if you dont mind?

anonymous · Answer

you cannot take the log of a negative number so all log graphs avertical asymptote since this one has shift of 1 the asymptote shift one to the left

anonymous · Answer

did that make sense?

anonymous · Answer

you there?

anonymous · Answer

sorry I had to take a call, but yes that makes sense! i totally forgot that you can't have the log of a negative number until you mentioned it. thank you so much for all of your help, I really appreciate it :)

anonymous · Answer

np good luck with class!! :)

anonymous · Answer

thank you very much :)