How would I find out if there is any value of x that would make the function f(x)=$$\sqrt[3]{x-2}+3$$ undefined?

Question

anonymous · Answer

Since you can take the Cube-Root of a negative number, i.e.  $$\sqrt[3]{-8} = -2$$This function is defined everywhere.

If it were a Square-Root, The function would be undefined for $$x < 2$$ 
(Remember, the Square-Root of a negative number is undefined on the real axis)

anonymous · Answer

so all real numbers is where x is undefined or just 2?

anonymous · Answer

The function is DEFINED everywhere. In other words, there are no values of x to make the function UN-defined. Those numbers I posted were just examples to illustrate the point..


Just to clarify, are there any real number values of x that will make $$\sqrt[3]{x}$$ undefined??