Question

Alright I'm confused.

Use 1-1 property of the exponential function to solve the given equation.

3^x+2=729/3^x

I'm clueless

Answer 1

To me, time both sides by 3^x to get \(3^x(3^x+2)=729\) then plus 1 both sides to get
\((3x +1)^2=730\)

Answer 2

sorry, \((3^x+1)^2=730\)

Answer 3

square root both sides to get \(3^x +1 = \sqrt{730}\) you can step up from this, right?

Answer 4

Yeah I see what you're saying

Answer 5

We have to solve it using log( )though

Answer 6

I have no idea..
mlp!

Answer 7

oh hey lol

Answer 8

So I got to log3(3^x-2)=log3(729\3x) But I seem to be lost past that

Answer 9

It seems you need some more steps.
-2 both sides, \(3^x= \sqrt{730}-2\) therefore \(\large log_3({\sqrt{730}-2})=x\)

Answer 10

@jdoe0001

Answer 11

help me, friend.

Answer 12

let me retype this in an easier way to understand lol
I just learned the power alt keys and what not

Answer 13

3ⁿ+²=729/3ⁿ

Answer 14

oh, different problem.

Answer 15

That plus is part of the power, I just couldn't make it look like it
lol

Answer 16

\(\large 3^{n+2}= \dfrac{729}{3^n}\) right?

Answer 17

\(3^{n+2}= 3^n*3^2=3^n *9\) got me?

Answer 18

There you go!

Answer 19

I am waiting for your reply

Answer 20

yeah I got it so far

Answer 21

divided both sides by 9 what do you have?

Answer 22

3^x=81?