Question

GIVING MEDALS!!!!
Find the Perimeter of Trapezoid ABCD. Explain how you did it :D

Answer 1

easy, just add all sides' length

Answer 2

How do you add them?

Answer 3

@jdoe0001

Answer 4

now AB and DC, well, just look at the numbers and get the diffrence

now DA and BC, for those you'd get the distance formula \(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&(-3\quad ,&4)\quad D&(-4\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\ \quad \\ \quad \\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
B&(5\quad ,&4)\quad C&(7\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

Answer 5

hmmm D is ... at -5 actually, so

Answer 6

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&(-3\quad ,&4)\quad D&(-5\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\ \quad \\ \quad \\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
B&(5\quad ,&4)\quad C&(7\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

Answer 7

so notice A, is at (-3, 4) and B is at (5, 4) so it's really moving over the x-axis from -3 to 5, so the length is -3 to 0, 3, and then 0 to 5, well, 5
so 3 + 5 = 8 AB = 8

D is at (-5, 2) and C is at (7,2 ), same as before, is moving over the x-axis

from -5 to 0, well, 5 units, from 0 to 7, well, 7, so 5 + 7 = 12
DC = 12

Answer 8

Ok so, AB=8 and DC=12? Now how do I find ABCD?

Answer 9

well, use the distance formula, like \(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&(-3\quad ,&4)\quad D&(-5\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\ \quad \\ \quad \\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
B&(5\quad ,&4)\quad C&(7\quad ,&2)
\end{array}\qquad
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)

Answer 10

to get AD and BC

Answer 11

I don't understand....

Answer 12

\(x_1\) stands for the x-value for the 1st point, \(y_1\) y-value for 1st point
\(x_2\) stands for the x-value for the 2nd point, \(y_2\) y-value for 2nd point

Answer 13

I know. Ugh I hate Geometry..

Answer 14

so you just need to plug in the values and get the distance, or length of it

Answer 15

Ok. Then what do I do with the 2 numbers I got? Add them or subtract?

Answer 16

well, is a perimeter, so the perimeter is the SUM of all the segments

Answer 17

Ahhhhhhhhh THANKS SO MUCH!
:D

Answer 18

yw

Answer 19

Wait. How do you find the square root of -10....

Answer 20

@jdoe0001