can any1 tell me how to find the zeros y= 3x^4-2x^3+3
can you show how you got the answer you get
well. the possible zeros are plus or minus the factors of 3. then you just plug the factors for synthetic division. then if the remainder is zero then that is a zero. and use Descartes rule of signs to find out the possible positive and negative zeros and remember imaginary zeros come in conjugates.
sorry but im still confused..i have no clue how to do it when it comes to zeros
does your teacher not lecture at all? what do you know about synthetic division?
she dose..i know everything else so fer but when it came to the zeros i just didnt understand what my professor was trying to explain...so like how would you work out the answer?
first thing I would do is evaluate the degree which is 4. so now we know there CAN BE up to 4 zeros. now we check the change in signs by Descartes rule of signs to get the possible positive zeros and there are 2, so first thing I would do is synthetic division with 3 and see if the remainder is 0 if it is that is a zero. then do it with 1 if it is that is a zero. then with my new polynomial from dividing by both I would have a quadratic term and you will use the quadratic formula to get the complex conjugates or the negative zeros
thnks for trying...im probably gunna have to ask some1 in my class b4 the quiz tomorrow because maybe i learn better in person..thank you anyways
khanacademy.org will help you out im sure.
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