Question

help?!?!?!?!?!?

Answer 1

Subtract exponents when dividing and add when multiplying.

Answer 2

B

Answer 3

Yes, what do you not understand?

Answer 4

what do you mean b?
its not multiple choice did you not click on the picture?

Answer 5

try to simplyfy each one answer can u do that ??

Answer 6

ok i'll simplify mike answer to u
\[\frac{ x^\frac{ 8 }{5 }.x \frac{ 4 }{ 8 } }{ x \frac{ 2 }{5 } }\]
\[(x^\frac{ 8 }{ 5 }.x^\frac{ 4 }{ 8 })\div x^\frac{ 2 }{ 5 } \]
\[(x^\frac{ 8 }{ 5 }+\frac{ 4 }{ 8 } )\div x^\frac{ 2 }{ 5 }=x^\frac{ 28 }{15 } \]
\[x^(\frac{ 28 }{15}-\frac{ 2 }{ 5 })=x^\frac{ 22 }{ 15 }\neq x^2\]

Answer 7

scott answer
\[(\sqrt[6]{x})^3=x^\frac{ 3 }{ 6 }=x^\frac{ 1 }{ 2 }\neq x^2 \]

Answer 8

when base is same then power will add up on multuplication and subtract in division

Answer 9

@ikram002p

Would you check what you wrote at the beginning as Mike's problem? Thanks.

Answer 10

kim answer
\[\sqrt[5]{x}.x^\frac{ 2 }{5 }.x^\frac{ 3 }{5 }.x^\frac{ 4 }{5 }=\sqrt[5]{x}.x ^\frac{ 9 }{ 5 }\]
\[\ x ^\frac{ 9 }{ 5 .5}\]

Answer 11

@Directrix ohhh..i put 8 insted of 5 !!

Answer 12

Just re-do it, @ikram002p

Answer 13

@ikram002p Here is what I got for Kim.

Answer 14

huh .. ok :)

Answer 15

@lowcard2 It appears to me that there is one student in the problem whose work is not correct and three students whose work is correct. Would you look and see if you posted the question correctly? Thanks.

Answer 16

@Directrix ur r right buddy

Answer 17

kim answer?

Answer 18

Kim's answer is x^2. Kim is also correct.

This appears to be the same question:
http://openstudy.com/updates/5256f926e4b002bdb08e3b49

Answer 19

Should i write scott and kim are correct?

Answer 20

Three people are correct and one person is wrong.
Mike, Kelly, and Kim got x^2.

Scott got x^(1/2) which does not equal x^2.