nnn

Question

nnn

hartnn · Answer

you can apply partial fractions only if degree of numerator is LESS than degree of denominator

anonymous · Answer

Partial fractions can be used but you have to apply long division first.

hartnn · Answer

yes, do long division to get a fraction where numerator degree is less than denominator's

anonymous · Answer

x^2 - (1/x+1) + (2/x+4) -1

hartnn · Answer

seems you did the long division part correct
x^2-1 is correct
but not the other terms
what did you get in the numerator ? 
x^2 -1- ????/ (x+4)(x+1)

anonymous · Answer

actually x^2-1 (x-2/ (x+1)(x+4))

hartnn · Answer

the remainder is incorrect, its not x-2
its 9x+10
you should've got 
x^2 -1 + (9x+10)/[ (x+1)(x+4) ]

anonymous · Answer

ohh yeah I see that

anonymous · Answer

but when doing the long division wouldn't you multiply the whole thing by -1. So then when you subtract the product doesn't it all turn to positives leaving x-2

hartnn · Answer

i don't see the point in multiplying whole thing by -1
did you not get the remainder as 9x +10 ?
if not can you show me the long division, so that i can find the error in your work

anonymous · Answer

attachment

hartnn · Answer

in that when you multiplied by x^2+5x+4 by -1
 you got 
-x^2 -4x-4
it should be 
-x^2 - 5x - 4
right ??

anonymous · Answer

no
I brought down then -4x-4 
then under it is the -x^2 - 5x - 4 
then I subtracted
 them

hartnn · Answer

oh yeah!
the error is that you took (x^4 + 5x^3 + 3x^2 -4x -6)

instead of (x^4 + 5x^3 + 3x^2 + 4x +6)
which is in the question

anonymous · Answer

actually I submitted the wrong signs -__- I'm sorry

hartnn · Answer

then you're absolutely correct! :)

hartnn · Answer

x^2 -1 + (x-2)/[ (x+1)(x+4) ]

hartnn · Answer

and then what did u get as final answer ?

anonymous · Answer

I found A = -1 and B=2

so I get what I gave you on top

hartnn · Answer

yes, yes
this is correct
x^2 - (1/x+1) + (2/x+4) -1
i was asking answer after integration...

anonymous · Answer

x^3/3 -x -ln |x+| + 2 ln |x+4| +C

hartnn · Answer

$x^3/3 -x -\ln |x+1| + 2 \ln |x+4| +C  ~~ is ~~ \checkmark ~~ \ddot \smile $

anonymous · Answer

now do I just pug in -3 and -2?

hartnn · Answer

yes, put the upper limit first

anonymous · Answer

f(-2) - f(-3)

hartnn · Answer

correct!

rina.r · Answer

when open study is gonna be fixed?

hartnn · Answer

soon, but idk for sure

rina.r · Answer

plz do something

hartnn · Answer

if i could've, i would've ....

hartnn · Answer

thats not even a good joke
smallmelo, what did you get your final answer ?

anonymous · Answer

7.413

hartnn · Answer

that is absolutely correct! :)