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Mathematics 8 Online
OpenStudy (anonymous):

PLz help gold medal will be awarded..........

OpenStudy (anonymous):

see attachment

OpenStudy (anonymous):

C I believe it is C

OpenStudy (austinl):

I would not agree with that statement. You have to distribute.

OpenStudy (anonymous):

oh ok can u show me how

OpenStudy (anonymous):

plz

OpenStudy (anonymous):

ohh right.

OpenStudy (austinl):

\(\sqrt{a}(b\sqrt{c}-d)=b\sqrt{a\times c}-d\sqrt{a}\)

OpenStudy (anonymous):

?? doing it with the numbers would make it easier

OpenStudy (anonymous):

it would be A. If you had to distribute. Right

OpenStudy (austinl):

That is the basic form, just follow that. And no, it would not be A.

OpenStudy (anonymous):

B?

OpenStudy (austinl):

Nope.... Kinda narrowed it down didn't it?

OpenStudy (anonymous):

But YOU said distribute, wait it's D

OpenStudy (anonymous):

D

OpenStudy (anonymous):

has to be thats the only one left... thx

OpenStudy (austinl):

If you distribute and follow the form, you can see that it has to be D. It fits! :D

OpenStudy (anonymous):

oh.. i have some more dont go yet

OpenStudy (anonymous):

here

OpenStudy (gorv):

\[\sqrt{72*n^{13}}=\sqrt{2*36*n ^{12}*n}=6*n ^{6}*\sqrt{2n}\]

OpenStudy (anonymous):

ok so D?

OpenStudy (gorv):

yippee

OpenStudy (anonymous):

ok thx one more

OpenStudy (anonymous):

here

OpenStudy (gorv):

\[\sqrt{108}=\sqrt{36*3}=6\sqrt{3}\]

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