Mathematics
8 Online
OpenStudy (anonymous):
PLz help gold medal will be awarded..........
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OpenStudy (anonymous):
see attachment
OpenStudy (anonymous):
C I believe it is C
OpenStudy (austinl):
I would not agree with that statement. You have to distribute.
OpenStudy (anonymous):
oh ok can u show me how
OpenStudy (anonymous):
plz
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OpenStudy (anonymous):
ohh right.
OpenStudy (austinl):
\(\sqrt{a}(b\sqrt{c}-d)=b\sqrt{a\times c}-d\sqrt{a}\)
OpenStudy (anonymous):
?? doing it with the numbers would make it easier
OpenStudy (anonymous):
it would be A. If you had to distribute. Right
OpenStudy (austinl):
That is the basic form, just follow that. And no, it would not be A.
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OpenStudy (anonymous):
B?
OpenStudy (austinl):
Nope....
Kinda narrowed it down didn't it?
OpenStudy (anonymous):
But YOU said distribute, wait it's D
OpenStudy (anonymous):
D
OpenStudy (anonymous):
has to be thats the only one left... thx
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OpenStudy (austinl):
If you distribute and follow the form, you can see that it has to be D. It fits! :D
OpenStudy (anonymous):
oh.. i have some more dont go yet
OpenStudy (anonymous):
here
OpenStudy (gorv):
\[\sqrt{72*n^{13}}=\sqrt{2*36*n ^{12}*n}=6*n ^{6}*\sqrt{2n}\]
OpenStudy (anonymous):
ok so D?
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OpenStudy (gorv):
yippee
OpenStudy (anonymous):
ok thx one more
OpenStudy (anonymous):
here
OpenStudy (gorv):
\[\sqrt{108}=\sqrt{36*3}=6\sqrt{3}\]