If x varies inversely as y and directly as t, and x = 12 when t = 10 and y = 25, find y when x is 6 and t = 3. 9 3/5 15 166 2/3
The first step is to create your model.
Looks like x = k*t*(1/y)
You are given values for x, t, and y so that you can solve for k.
Are you with me?
not sure....
What is giving you difficulty?
the solve for k....how should i do it???
You are given a word problem that you need to use to create a model. Your problem says x increases directly with t and inversely with y. Start with a general equation that grows directly with t and inversely (1/y) with y.
The general equation described above is x = k*t*(1/y) This simple expression is useful because it generally describes all situations where x and y are inversely related and x and t are directly related. Your question goes into more detail giving you values of x, y, and t so that you can solve for the constant factor k.
Step one is to setup the model \[x = kt(\frac{ 1 }{ y })\] Step 2 is to plug in x = 12 when t = 10 and y = 25 and solve for k. Are you with me?
ok like this....12=k*10(1/25)
Yes! :-)
but what is the first step to solve for k???
use arithmetic to get k isolated so that you have # = k
I guess the first step would be to multiply both sides by 25.
like this...25*12=k*10*1/25*25 25*12=k*10
right
what should i do next???
divide both sides by 10
which =30????
Very good. Now step 3 is to take the second set of x's t's and (along with k) use the model equation to solve for y.
ok..
gat it is it 15???
:-D Nice job!
thankx for ur help and time...:)
You are welcome. Study hard!
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