This is about vectors.

Question

anonymous · Answer

@amistre64

anonymous · Answer

this is a tough one haha

amistre64 · Answer

its not tough, just hard to prove a definition :/

define a general vector v, take its magnitude and square it

take the dot product of v.v and compare the resutls

amistre64 · Answer

for some vector in R^n let
$$\vec v=v_1~i+v_2~j+v_3~k+...+v_n~p$$
$$|\vec v|=\sqrt{(v_1)^2+(v_2)^2+(v_3)^2+...+(v_n)^2}$$
$$|\vec v|^2=(v_1)^2+(v_2)^2+(v_3)^2+...+(v_n)^2$$

and by definition: 
$$\vec v \cdot \vec v=(v_1)^2+(v_2)^2+(v_3)^2+...+(v_n)^2$$

anonymous · Answer

@amistre64 you gave me a warning the other day for giving out an answer and yet here you're doing the same thing.  I was doing just like you... demonstrating how to arrive at an answer.  i'm not intending to be critical or negative, just frustrated for being "scolded" then for what you are doing now.

anonymous · Answer

wats wrong with giving answers?

anonymous · Answer

an explanation should always accompany the answer.  answers aren't as meaningful as the understanding of how to arrive at them is.
my inquiry doesn't have to do with you but with @amistre64 and the warning he issued to me the other day for the same thing he just did here.

amistre64 · Answer

we all need reminders :)  im not sure if what i did here was giving out an answer tho.  All I did was consider how I would approach it.

amistre64 · Answer

Im sure I could have tried to draw out the information from forz, but the way this site has been acting lately it is difficult to have any meaningful interactions to say the least :/