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Mathematics 74 Online
OpenStudy (anonymous):

Last year, tickets to a play were sold for $11 each and 400 people attended. An analysis has shown that for every $1 increase in ticket price attendance will decrease by 20 people. Determine the maximum possible revenue. What ticket price with produce the maximum revenue. Show work.

OpenStudy (anonymous):

do you have an function made up for the story problem?

OpenStudy (anonymous):

Do I have one? Nope.

OpenStudy (anonymous):

"Last year, tickets to a play were sold for $11 each and 400 people attended." so the function for this would look like: revenue = (cost)*(people) "An analysis has shown that for every $1 increase in ticket price attendance will decrease by 20 people." so the function for this will be the same revenue = (cost)*(people) but we have to introduce in the increase in ticket price and the decrease people. so, how would we write the "cost" part to illustrate a varying increase from 11 dollars?

OpenStudy (anonymous):

revenue= (cost+1)*(people-20) ?

OpenStudy (anonymous):

yep, now i'm gonna refine it and you'll get it when I do. revenue= (cost+1)*(people-20) revenue= (11+1)*(400-20) revenue= (11+x)*(400-20x)

OpenStudy (anonymous):

now it is in terms of x, where x is varying and can be incrimented to show the increase in cost and the decrease of attendence

OpenStudy (anonymous):

so to find the max, derivate the equation we made, set it equal to zero, and solve for x. then take x+11 and that equals the ticket price to maximize revenue

OpenStudy (anonymous):

Thank you so much!

OpenStudy (anonymous):

yep!

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