Last year, tickets to a play were sold for $11 each and 400 people attended. An analysis has shown that for every $1 increase in ticket price attendance will decrease by 20 people. Determine the maximum possible revenue. What ticket price with produce the maximum revenue. Show work.
do you have an function made up for the story problem?
Do I have one? Nope.
"Last year, tickets to a play were sold for $11 each and 400 people attended." so the function for this would look like: revenue = (cost)*(people) "An analysis has shown that for every $1 increase in ticket price attendance will decrease by 20 people." so the function for this will be the same revenue = (cost)*(people) but we have to introduce in the increase in ticket price and the decrease people. so, how would we write the "cost" part to illustrate a varying increase from 11 dollars?
revenue= (cost+1)*(people-20) ?
yep, now i'm gonna refine it and you'll get it when I do. revenue= (cost+1)*(people-20) revenue= (11+1)*(400-20) revenue= (11+x)*(400-20x)
now it is in terms of x, where x is varying and can be incrimented to show the increase in cost and the decrease of attendence
so to find the max, derivate the equation we made, set it equal to zero, and solve for x. then take x+11 and that equals the ticket price to maximize revenue
Thank you so much!
yep!
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