Mr. Crosson selects two students from his class to present their reports on Spain. He places the names of each student in a box and picks one at a time. The class has 8 boys and 10 girls. What is the probability that Mr. Crosson will pick two boys in a row if he does not put the first name back in the box? Round your answer to the nearest percent.
For the first student selection, there are 8 boys and 10 girls. The probability of selecting a boy is 8/18 because there are 8 boys in a group of 18. Assuming that a boy is selected on the first draw, then 7 boys' names remain in the box along with the names of 10 girls. So, the probability of the second boy name is 7/17 because 7 boy names remain in the box in a group of 17. To get the probability of BB in this scenario, multiply 8/18 * 7/17 and round to the nearest percent.
If you are into using the combination symbolism, you can crank out: (C(8,2)*C(10,0))/C(18,2) = @JC9977002 Post what you get and we can compare answers, okay?
When i mulitplied the 2 fractions from the scenario i got 56/306
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