Mr. Crosson selects two students from his class to present their reports on Spain. He places the names of each student in a box and picks one at a time. The class has 8 boys and 10 girls. What is the probability that Mr. Crosson will pick two boys in a row if he does not put the first name back in the box? Round your answer to the nearest percent Can someone help me out ?
i know once you mulitply the fractions you get 56/306 , do i simplify to find the percent ?
8 over 10
and yes
jc?
yes ?
The probability of picking a boy in the first draw is 8/18. Having picked a boy in the first draw, the probability of picking a boy in the next draw is 7/17. \[P(2\ boys\ sequentially)=\frac{8}{18}\times\frac{7}{17}=you\ can\ calculate\] It is usual to either simplify the fraction or to express the answer as a decimal number to a specified number of places.
I got 18.3 percent ?
In the question it asks for the answer to be expressed to the nearest percent. Therefore the answer is 18%.
thanks bro
You're welcome :)
Margo and Carrie are trying to go to Idaho for Dawn's wedding. The probability of finding a flight for less than $400 is 1/7. The probability of Carrie making enough money babysitting to pay for her flight is 3/5. The probability of the girls being able to take time off from work is 1/2. What is the probability that they will make it to their friend's wedding? Want to help me out with this one, i have online classes so i practically have to teach myself these forumals without 1 mistake or i fail lol.
This second question is not clearly expressed. However it appears that it is certain that Margo can afford to pay for the flight even if the cost is more than $400. Therefore the probability of both women getting to the wedding is dependent on Carrie's being able to pay for the flight and both women getting time off, which is \[\frac{1}{7}\times\frac{3}{5}\times\frac{1}{2}=you\ can\ calculate\]
3/70 ?
Join our real-time social learning platform and learn together with your friends!