Regan is trying to find the equation of a quadratic that has a focus of (-2, 5) and a directrix of y = 13. Describe to Regan your preferred method for deriving the equation. Make sure you use Regan's situation as a model to help her understand.
Quadratics are parabolas. One of the definitions of parabola is that it is a curve where the distance from a point on the curve to the focus is the same as the distance from the point to the directrix. So let the point be (x,y) Find the distance between (x,y) and the focus (-2,5) using the formula for the distance between two points. Find the distance between (x,y) and the line y = 13. It will be just |y - 13| Equate the two distances and simpligy to get the equation of the parabola.
What is the x and y values?
It is a generic point on the parabola. No specific point. When you find the distances and equate them you will get the equation of the parabola in the form: y = ax^2 + bx + c
so how do i do the first step?
|dw:1385176239980:dw|
All points on the parabola are equidistant from the focus and the directrix distance from focus d^2 = distance from directrix d1^2 (x + 2)^2 + (y - 5)^2 = (13 - y)^2 Expand and simplify.
thank you
you are welcome.
@ranga im having trouble simplifying it. what is the final answer?
x2+4x+4+y2-10y+25=169-26y+y2. @ranga this is what i have
Simplifying I am getting: y = -1/16x^2 - 1/4x + 35/4
When plotted t will be an inverted parabola (an upside down U) because the leading coefficient is negative (-1/16)
how do you simply what i got into what you got?
simplify
x^2 + 4x + 4 + y^2 - 10y + 25 = 169 - 26y + y^2 subtract y^2 from both sides x^2 + 4x + 4 - 10y + 25 = 169 - 26y subtract 169 from both sides x^2 + 4x - 10y + 4 + 25 - 169 = - 26y x^2 + 4x - 10y - 140 = - 26y Add 10y to both sides x^2 + 4x - 140 = -16y divide both sides by -16 -1/16x^2 - 4/16x + 140/16 = y y - -1/16x^2 - 1/4x + 35/4
thanks
yw.
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