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OpenStudy (anonymous):
for f(x) = 1/x^2-3, find
f (3)
f (2+h)
12 years ago
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OpenStudy (anonymous):
For f(3), plug in 3 where the x is.
12 years ago
OpenStudy (anonymous):
For f(2+h) your answer will have 1 divided by a quadratic of h in it.
12 years ago
OpenStudy (anonymous):
so 1 is 9 and idk 2
12 years ago
OpenStudy (anonymous):
2+h just replaces x. It's basically a change in variable
12 years ago
OpenStudy (anonymous):
so f = 2+h
12 years ago
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OpenStudy (anonymous):
is should be in the form\[f(2+h)=\frac{ 1 }{ (2+h)^2 }-3\]
12 years ago
OpenStudy (anonymous):
since x is replaced by 2+h
12 years ago
OpenStudy (anonymous):
you understand how i did this, right?
12 years ago
OpenStudy (anonymous):
oh okay, what about the first one? 9 is correct?
12 years ago
OpenStudy (anonymous):
No you have to solve for \[f(3)=\frac{ 1 }{ (3)^2 }-3\]
12 years ago
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OpenStudy (anonymous):
and whats that? :/
12 years ago
hartnn (hartnn):
is your f(x) \(=\dfrac {1}{x^2-3}\)
??
12 years ago
OpenStudy (anonymous):
\[f(3)=\frac{ 1 }{ (3)^2 }-3=\frac{ 1 }{ 9 }-3=-\frac{ 26 }{ 9 }\]
12 years ago
OpenStudy (anonymous):
so that's the answer? :S
12 years ago
OpenStudy (anonymous):
I'm really not good at math sorry!! :/
12 years ago
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OpenStudy (anonymous):
lol it's really about trying and grasping the topics you learn in school and continuously practicing them.
No one is born knowing how to completely do math. Everything is practice and applying what you have learned
But that is the answer
12 years ago
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