Any help would be awesome!(: The dielectric constant of ruby mica is 5.4. What would be the speed of light as it passes through ruby mica?

Question

schrodingers_cat · Answer

The Equation your looking for is v = c/n

n = refractive index

c= speed of light

k = dielectric constant

Use the relation k = n^2

So, if you plug in the numbers you get,

v = (3 x 10^8)/(sqrt(5.4)) = 129.09 x10^6 m/s

I hope this helps :)

anonymous · Answer

wow.. schrodingers cat.. are u dead or alive? :D

anonymous · Answer

It did help but on the problem, I have answer choices and neither match up /: there's 3.2x10^3 m/s,    9.4x10^4 m/s,    5.6x10^7 m/s,    and   1.3x10^8 m/s. I'm thinking it should be the last one? @Schrodingers_Cat

schrodingers_cat · Answer

Yes. I would try the last one I you round up you should get roughly 1.3 x 10^8 m/s

Hope this helps :)

anonymous · Answer

Okay, great. Thank you so much! (: