Question

Factor completely 2x^2 + 28x + 96.

a. 2(x + 6)(x + 8)
b. (2x + 12)(x + 8)
c. 2(x + 4)(x + 12)
d. (2x + 4)(x + 12)

Answer 1

First notice you can factor out a 2... try that. Or wait for someone to post the entire solution and answer all at once :P

Answer 2

\[2x ^{2}+28x+96\]

factor the 2 out.
\[2(x ^{2}+14x+24)\]
Factor again
\[2(x+8)(x+6)\]

So A

Answer 3

\[2x ^{2} + 28x + 96\]
\[2[x^{2} + 14x + 48]\]
\[2[x ^{2} + 8x + 6x + 48]\]
\[2[x(x+8) + 6(x+8)]\]
\[2(x+6)(x+8)\]