Question

how to find the range and domain of the following:
f(x)=sqr root of (1-3x)

Answer 1

domain: solve \(1-3x\geq 0\) for \(x\)

Answer 2

range is \([0\infty)\) or \(f\geq 0\) since the radical means the positive square root

Answer 3

can you solve \(1-3x\geq0\) ?

Answer 4

yup...thnx... :)
so, to find range of sqr root, there must be no -ve ?

Answer 5

yes
\[\sqrt{whatever}\geq 0\] always
for example \(\sqrt{9}=3,\sqrt0=0\) it is never negative

Answer 6

ok... what about to find range of

Answer 7

\[\sqrt{16-x ^{2}}\]