Question

I will give MEDALS! I just need help! FAST!

Answer 1

\[\sqrt{3}\left( 4 + \sqrt{12} \right)\] is what it actually looks like.

Answer 2

(how do I solve this) I don't understand exactly what I need to do here, but I get the concept. I just need steps :/

Answer 3

find the square root of 12 which is 3.46410161514 so 4 + 3.46410161514 = 7.46 for short then 3 square root =1.73205080757 so 1.73 x 7.46 = 12.9058

Answer 4

but how youre supposed to write for finding the square root of 12 is \[2\sqrt{3}\] because you have to factor it out, then take a 2 from its pair and leave the remaining 3 inside the square root ... soo yeah, then that leaves me with \[\sqrt{3}\left( 4 + 2 \sqrt{3} \right)\]
I dont know what to do after this.

Answer 5

() = what it was before

find √12 which is 3.46410161514 so 4 + 3.46410161514 = 7.46 for short

then√3 =1.73205080757 so 1.73 ( √3) x 7.46 (4 + 3.46) = 12.9058

Answer 6

hold on now i undestand what u said

Answer 7

My answer options are \[A. \sqrt{12} + 6\] \[B. 4\sqrt{3} + 6\] \[C. 2\sqrt{3} + 6\sqrt{3}\] so thats what I have to solve for.

Answer 8

where did you get the six from

Answer 9

is this distributive property?

Answer 10

6 * 6

Answer 11

why wouldn't it be distributive property?

Answer 12

i dont know

Answer 13

\[\sqrt{3}\times \sqrt{12}=\sqrt[]{36}=duhhh\]

Answer 14

what about the 4 no Duhh

Answer 15

/.\ guys...

Answer 16

so would it be B?? I understand how it could be that

Answer 17

\[\sqrt{3}\times4=\sqrt[2]{3 \times 16}=duhhh\]

Answer 18

B

Answer 19

but i thought you couldnt multiply a radical by a whole number? @nincompoop

Answer 20

what about the 4 no Duhh

Answer 21

B

Answer 22

how did you type that?

Answer 23

type what?

Answer 24

that math stuff

Answer 25

ooh i see now

Answer 26

Click equation under the text box where you type

Answer 27

\[\sqrt{3}*4 + \sqrt{3}*\sqrt{12}=duhhhh\]

Answer 28

\[\sqrt{3}*\sqrt{16}=\sqrt{3}*4\]

Answer 29

\[\sqrt{48}+\sqrt{36}=4\sqrt{3}+6\]

Answer 30

get it now?

Answer 31

you can multiply a radical square root by a whole number if you can convert the whole number into square
see how I made the 4 into sqrt(16)

Answer 32

although that step was unnecessary, I am just showing you the consistency since we are doing it with sqrt (12) * sqrt (3)

Answer 33

Lol do I get a medal for figuring it out? /.\

Answer 34

wow that was a lot
\[\sqrt{3}\left( 4 + \sqrt{12} \right)=\sqrt{3}\times 4+\sqrt{12\times 3}=4\sqrt{3}+\sqrt{36}=4\sqrt3+6\]