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Mathematics 16 Online
OpenStudy (anonymous):

Please help?

OpenStudy (anonymous):

The bases of a trapezoid have lengths 50 and 75. Its diagonals have lengths 35 and 120. Find the area of the trapezoid.

OpenStudy (jdoe0001):

is there a picture?

OpenStudy (anonymous):

Sure just a sec

OpenStudy (anonymous):

|dw:1385240010377:dw| Sorry it's not all that accurate xD

OpenStudy (jdoe0001):

hmmm.... how about a screenshot?

OpenStudy (anonymous):

There's no picture, sorry :P

OpenStudy (jdoe0001):

ohh.. ok

OpenStudy (anonymous):

is it an isosoles trapezoid

OpenStudy (jdoe0001):

hmmm... if it were an isosceles trapezoid... how come the diagonals differ? one is 35 and the other 120..... doesn't sound like one

OpenStudy (anonymous):

No, because the diagonals are different like jdoe said

OpenStudy (anonymous):

The textbook told us to use similar triangles, and I only found the top and bottom triangles to be similar. I'm not sure how that would help us find the area though..

OpenStudy (jdoe0001):

hmm ok .. so I'm thinking that |dw:1385241489796:dw|

OpenStudy (anonymous):

you cant just assume that it has right angles

OpenStudy (anonymous):

It doesn't show any right angles..

OpenStudy (jdoe0001):

so you just need to find "h" or height, in this case at the bottom of it , using pythagorean theorem, keeping in mind the \(\bf \textit{Area of a Trapezoid}=\cfrac{h}{2}(base1+base2)\)

OpenStudy (jdoe0001):

well, you do have to assume because shape-wise for the given values, is what fits, and to be a trapezoid, it just have to have 2 parallel sides, the other 2 sides don't have to be slanted or equal

OpenStudy (anonymous):

im sorry i cant help because i havent done this type of geometry in a while

OpenStudy (anonymous):

I guess that makes sense, thank you so much! :D

OpenStudy (anonymous):

Noooooooooooooooo

OpenStudy (anonymous):

You cant assume. I remember doing problems like this It can be done without assuming that the angles are 90

OpenStudy (anonymous):

the only proble is that i forgot

OpenStudy (jdoe0001):

with an isosceles trapezoid is simple since there's a property to use for the diagonals, with non-isosceles there isn't

OpenStudy (anonymous):

ya i know it isnt an isoseles

OpenStudy (anonymous):

Lol, I think that's the only way we can think of right now xD Thanks though, hopefully it's correct

OpenStudy (anonymous):

have you guys talked about adding things extra parts in class

OpenStudy (jdoe0001):

extra parts?

OpenStudy (anonymous):

Well the textbook told us to use similar triangles to find the length of the concurrency to each corner

OpenStudy (anonymous):

im talking about adding midlines

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