Question

Find the slope of a line passing through the points (1,3) and (6,-2)

Answer 1

Well, we plug these into point-slope form and continue to convert it into slope intercept

Answer 2

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(1\quad ,&3)\quad &(6\quad ,&-2)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\)

Answer 3

\[Slope = \frac{ y _{2}-y _{1} }{ x _{2}-x }\]

Answer 4

Yeah that's what it looks like :P

Answer 5

So -1 would be the correct answer?

Answer 6

-1 would be correct, yes :)

Answer 7

what about ...Find the slope of a line passing through the points (1,12) and (1,-13).

Answer 8

same idea :)
plugin x1=1 , y1=12 , x2=1 , y2=-13

Answer 9

-12/0?

Answer 10

yes and since you cannot divide by a 0
it would be a vertical line
because only a vertical line's slope has a denominator of 0 :)

Answer 11

What if you have -13/-8, can that be the equivalent of positive 13/8?

Answer 12

yes it would :) hey you're getting pretty good at this! :D

Answer 13

okay new question...What is the slope of a line that does not intersect the y-axis?

Answer 14

only vertical lines do not intersect the y-axis
therefore according to what I had said before, the slope's denominator would be a 0

Answer 15

So x=1 can be a correct answer?

Answer 16

yes :)

Answer 17

What about...do the following ordered pairs represent the same point? (1,3) and (3,1).

Answer 18

if you tried graphing them:

so no, they are not the same.

Answer 19

heres a new one....write the equation of a line in slope-intercept form with the given slope and point P: Slope = 2; P(7,8)

Answer 20

slope-intercept form: y = mx + b
m = slope = 2
so you get y = 2x + b
then you can temporarily plug in the given point to find b
so when given the point (7, 8) you plug in and get
8 = 2(7) + b
solve for b
and once you get b
plug in what you got for b into y = 2x + b