Question

heres a new one....write the equation of a line in slope-intercept form with the given slope and point P: Slope = 2; P(7,8)

Answer 1

slope-intercept form: y = mx + b
m = slope = 2
so you get y = 2x + b
then you can temporarily plug in the given point to find b
so when given the point (7, 8) you plug in and get
8 = 2(7) + b
solve for b
and once you get b
plug in what you got for b into y = 2x + b

Answer 2

so y=2x+(-6) ?

Answer 3

yep :)

Answer 4

What if you had..Write the equation of the line (in slope-intercept form) passing through P and Q: P(3,7) Q(2,12)

Answer 5

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
P&(3\quad ,&7)\quad Q&(2\quad ,&12)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)

Answer 6

This equation is that of a function: y = 2x+3...... true or false?