Question

last 2

Answer 1

so the first i can rule out 4,6

Answer 2

and 12

Answer 3

well, you can rule out the answer A not 4 for any reason. but 6 cant work. if you get what im saying. why 12? anyways. do you remember how to get lcd?

Answer 4

the lcd is x(x-6)

Answer 5

so i would have

8(x-6) + x(x-6) x 2? on the left?

Answer 6

8(x-6)+2x(x-6) yes

Answer 7

then on the right:
4 i think

Answer 8

on the right you would have x(x+4)

Answer 9

8(x-6) + 2x(x-6) = x(x+4)
8x - 48 + 2x^2 - 12x = x(x+4) right?

Answer 10

8x - 48 + 2x^2 - 12x = x^2 + 4x

Answer 11

perfect

Answer 12

since there are less terms on the right make your 0 on the right

Answer 13

ok so then grouping like terms:

8x - 4x - 48 + 2x^2 - x^2 = 0 right?

Answer 14

where did your -12x go?

Answer 15

8x - 48 + 2x^2 - 12x = x^2 + 4x

8x - 4x - 48 + 2x^2 - x^2 - 12x = 0 ?

Answer 16

better. now combine like terms and factor

Answer 17

4x - 48 + x^2 - 12x = 0

4x - 11x - 48 = 0

Answer 18

hmm. you did some arithmatic wrong there you should have x^2-8x-48

Answer 19

can only combine terms with the same degree. im sure you know that and it was just one of those duh mistakes.

Answer 20

8x - 4x - 48 + 2x^2 - x^2 - 12x = 0

8x - 4x - 12x + 2x^2 - x^2 + 48 = 0

-8x - x^2 - 48 = 0

x^2 - 8x - 48= 0

Answer 21

sweet. now factor it and solve and you have your two answers.

Answer 22

ok so using the "box" method i think :

(x + 4)(x - 12)

Answer 23

yes. that's it on the second problem. there is a numerator you can factor and calcel before even starting

Answer 24

cancel

Answer 25

for the first it is (-12, 4) ?

Answer 26

no it would be 12, -4

Answer 27

have to set the two factors = to 0

Answer 28

how when -12 + 4 would = -8?

Answer 29

like when i check it i get an odd answer

Answer 30

because you have to set (x+4)=0
and (x-12)=0

Answer 31

oh, right...

x - 12 = 0
x = 12


x + 4 = 0
x = -4

Answer 32

ya if you plug -4 in you get 0=0

Answer 33

i see

Answer 34

so on the last one, x+2 would cancel out

Answer 35

no the numerator x^2-16 is the difference of two squares

Answer 36

(x+4)(x-4)

Answer 37

wouldn't i have to find the lcd first and wouldn't that be (x+4)(x+2)?

Answer 38

no, were going to make a shortcut. factor x^2-16 first to (x+4)(x-4)
then you will make the problem more simple when you cancel out the x+4

Answer 39

so
(x + 4)(x-4) / (x+4)(x+2) = x - 3/ x - 2 - 1

Answer 40

um well ignoring the fact you missed some parenthesis on the right side with the -1 yes that is correct. now you just mark out x+4 on the left side then find the lcd
dont forget to separate the -1

Answer 41

\[\frac{ (x-4) }{ (x+2) }=\frac{ (x-3) }{ (x+2) }-\frac{ (x+2) }{ (x+2) }\]

Answer 42

so:
(x -4) / (x+2) = (x-3) / (x+2)

Answer 43

and you should have noticed that -4 makes it undefined to begin with. but there is a lot of value to solving this problem

Answer 44

you forgot your -(x+2/x+2)

Answer 45

i wrote it incorrectly

(x -4) / (x+2) = (x-3) - (x+2)

Answer 46

you wrote it incorrectly again lol here
\[(x-4)=(x-3)-(x+2)\]
then distribute the - sign to get
\[x-4=x-3-x-2\]
combine like terms to get
x-4=-5
to get x=-1

Answer 47

sorry for giving you the answer. im getting tired.

Answer 48

no problem im sorry that this took this long, thank you :)

Answer 49

no problem, im doing this to refresh for my algebra final in a few weeks. so it helps me as well

Answer 50

im doing the same i was never really good with factoring lol

Answer 51

lol. right on.

Answer 52

lol, well im going to turn in the last 2 essays io have for history and go to sleep thx for the help, and goodnight:)

Answer 53

yep, later