Question

Find the derivative of g(x)=sqrt(5-3x)

Answer 1

\[\sqrt{5-3x} = (5-3x)^{\frac{ 1 }{ 2 }}\]
chain rule i think

Answer 2

Are you familiar with the chain rule?

Answer 3

\[g(x) = \sqrt{5-3x}\]
\[g'(x)= -\frac{ 3 }{ 2 }(5-3x)^{-\frac{ 3 }{ 2 }}\]

Answer 4

No @Isaiah.Feynman

Answer 5

d
dx [f(u)] = f'(u) u'

Answer 6

Yes lena

Answer 7

Take the derivative of (5-3x) and (5-3x)^1/2 and multiply

Answer 8

d (5-3x)
dx

Answer 9

d (5-3x)^1/2
dx

Answer 10

These equal something?

Answer 11

Right?

Answer 12

Yes, take the derivatives of (5-3x)^1/2 and (5-3x) then just multiply

Answer 13

You result with
\[g'(x) = \frac{ (5-3x)^{\frac{ -1 }{ 2 }} }{ 2 } \times (-3)\]

Answer 14

Simplifying..
\[g'(x) = \frac{ -3 }{ 2(5-3x)^{1/2} } = \frac{ -3 }{ 2\sqrt{5-3x} }\]

Answer 15

that's all?

Answer 16

Yeah.

Answer 17

https://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/chainrulesoldirectory/ChainRuleSol.html#SOLUTION 1
Take a look at this, it'll help understand the chain rule and such. It's helped me learn it in the past ^_^