Ask
your own question, for FREE!
Mathematics
11 Online
-
Still Need Help?
Join the QuestionCove community and study together with friends!
Prove that: \[□PRHQ = \sqrt{GQ \times QH \times HR \times RK}\] Plaese?
do you have the figure?
|dw:1385326716595:dw|
|dw:1385297699008:dw| Area (PRHQ)= area (HKG) - area1 - area2 = 1/2 (HK.GH) - 1/2 (RK.QH) - 1/2 (HR.GQ) = 1/2 (HR+RK)*(GQ+QH) - 1/2 (RK.QH) - 1/2 (HR.GQ) = 1/2 (HR.QH+RK.GQ) In the same time you got: Area(PRHQ) = HR.QH = 1/2 (HR.QH+HR.QH) So HR.QH = RK.GQ Finally \[Area (PRHQ) = HR.QH = \sqrt{HR.QH}*\sqrt{HR.QH}=\sqrt{HR.QH}\sqrt{RK.GQ}=\sqrt{RK.GQ.HR.QH}\]
\[= \sqrt{HR . QH} . \sqrt{RK}\] IS THE LAST EQUATION?
Still Need Help?
Join the QuestionCove community and study together with friends!
thank you :D
Nah, there just wasn't enough space it's: \[Area (PRHQ) = \sqrt{HR.QH}\sqrt{RK.GQ}=\sqrt{HR.QH.RK.GQ}\] And you're welcome :)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
4 minutes ago
0 Replies
0 Medals
3 days ago
3 Replies
2 Medals
6 days ago
3 Replies
0 Medals
1 day ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal