Question

How do I find the equation of the given circle? (Picture attached.)

A. (x-3)^2+(y-2)^2=2

B. (x+3)^2+(y+2)^2=2

C. (x+3)^2+(y+2)^2=1

D. (x-3)^2+(y-2)^2=1

Answer 1

First, in the graph, what is the center of the circle ?

Answer 2

The general equation of a circle is: (x - h)^2 + (y - k)^2 = r^2
where (h, k) is the center and r is the radius.

Can you find the coordinates of the circle's center from the diagram?
How about the circle's radius?

Answer 3

would the center of the circle be (3,2) ?

Answer 4

yes.

Answer 5

I don't know jhow to find the radius

Answer 6

yes, 3,2 is the center

now match to the formula that has (x-3) and y-2
in it.

Answer 7

How many units is the circle from the center? That will be the radius.

Answer 8

next, what is the distance from the center to the edge of the circle

Answer 9

so radius is 1

Answer 10

then square that number. look for the equation that has that number on the right side

Answer 11

hold on, let me write all of this out!

Answer 12

yes. put the center and the radius into the circle formula I gave earlier.

Answer 13

So it would be... D?

Answer 14

yes.

Answer 15

thank you both! :)