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Chemistry 15 Online
OpenStudy (anonymous):

how to write a net ionic equation

OpenStudy (anonymous):

Okay, so lets say we have the reaction for NaCl. \[HCl (aq) + NaOH(aq) \rightarrow H _{2}O(l) + NaCl(aq)\] HCl is a strong acid and NaOH is a strong base. Due to this, they are capable of dissociating (separating) completely in a solution. NaCl in addition, is a salt, also meaning that it separates completely in a solution. If you are ever unsure whether whether a compound is a strong acid/base, look up a chart online to help you out. So because these compounds separate completely, the equation can be written like this instead: \[H ^{+}(aq) + Cl ^{-}(aq) + Na ^{+}(aq) + OH ^{-}(aq) \rightarrow H _{2}O(l) + Na ^{+}(aq) + Cl ^{-}(aq)\] This is called an ionic equation. To get the net ionic equation, simply cross out the ions that are the same on each side. Both the Na+ and Cl- would be crossed out leaving you with the net ionic equation of \[H ^{+}(aq) + OH ^{-}(aq) \rightarrow H _{2}O(l)\] Also, the ions that are crossed out in the ionic equation are known as spectator ions.

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