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Let f(x) = \frac { 1 } { 6} x + 9 , \quad 1 \le x \le 2 The domain of f^{-1} is the interval [A,B]
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do you know domain of inverse function is same as range of original function ? so you just need to find range of f(x) can u ?
how do you find the range?
you just plug in extreme values of x in domain! so put x =1, f(1) =... put x=2, f(2) =..?
Thank you!
welcome ^_^
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if you want me to verify your range, tell me what u get :)
thats okay thank you though! i submitted it already and it said it was right.
awesome! :)
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