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ap calc question. medal reward. question will be provided.
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find the derivative of \[\sec ^{-1}\sqrt{x}\]
do you know chain rule ?
yes
derivative of sec x ?
sorry derivative of sec inverse x ?
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yeah thats what i dont know.
???
\( \large \frac{d}{dz} sec^{-1} z = \frac{1}{z^2\,\sqrt{1 - z^{-2}}}; \quad z \neq -1, 0, +1 \)
i thought it was\[\frac{ 1 }{ x \sqrt{x ^{2}-1} }\]
its the same thing use the one you posted
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how do you incorporate the \[\sqrt{x}\]
using chain rule , you multiply the derivative result by derivative of \(\sqrt x\)
so \[\frac{ 1 }{ 2\sqrt{x}}\]
\(\huge \dfrac{ 1 }{ \sqrt x \sqrt{x-1} }\times \dfrac{1}{2\sqrt x}\)
and simplify
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alright thanks
welcome ^_^
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