What is the length of the transverse axis?
(x-2)^2/36 - (y+1)^2/64=1
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OpenStudy (anonymous):
OpenStudy (anonymous):
do you have an idea of what the value would be?
OpenStudy (anonymous):
not at all! im not familiar with "transverse axis"
OpenStudy (anonymous):
the transvers axis goes with the directions the hyperbola opens up
OpenStudy (anonymous):
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OpenStudy (anonymous):
@ali1029
make sense what the transverse axis?
OpenStudy (anonymous):
yes, but how exactly do i figure out what the length of it is?
OpenStudy (anonymous):
the length of the transverse axis will be the value of 2 times 'a' when the equation is in the form
\[\frac {(x-h)^2}{a^2} - \frac {(y-k)^2}{b^2} = 1\]
OpenStudy (anonymous):
72?
OpenStudy (anonymous):
36 = 6^2,
thus a=6
see it now?
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OpenStudy (anonymous):
oh so its the squaare of 36 times 2, so the length of the transverse axis would be 12?
OpenStudy (anonymous):
so to find the length of the transverse I would use a and not c?
OpenStudy (anonymous):
mmm... a not c.. lemme double check!
OpenStudy (anonymous):
okay thanks, because if its a it is 12 but c would be 16 but i want to make sure i get the right answer :)
OpenStudy (anonymous):
its a like we said
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