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Mathematics 18 Online
OpenStudy (anonymous):

What is the length of the transverse axis? (x-2)^2/36 - (y+1)^2/64=1

OpenStudy (anonymous):

OpenStudy (anonymous):

do you have an idea of what the value would be?

OpenStudy (anonymous):

not at all! im not familiar with "transverse axis"

OpenStudy (anonymous):

the transvers axis goes with the directions the hyperbola opens up

OpenStudy (anonymous):

OpenStudy (anonymous):

@ali1029 make sense what the transverse axis?

OpenStudy (anonymous):

yes, but how exactly do i figure out what the length of it is?

OpenStudy (anonymous):

the length of the transverse axis will be the value of 2 times 'a' when the equation is in the form \[\frac {(x-h)^2}{a^2} - \frac {(y-k)^2}{b^2} = 1\]

OpenStudy (anonymous):

72?

OpenStudy (anonymous):

36 = 6^2, thus a=6 see it now?

OpenStudy (anonymous):

oh so its the squaare of 36 times 2, so the length of the transverse axis would be 12?

OpenStudy (anonymous):

so to find the length of the transverse I would use a and not c?

OpenStudy (anonymous):

mmm... a not c.. lemme double check!

OpenStudy (anonymous):

okay thanks, because if its a it is 12 but c would be 16 but i want to make sure i get the right answer :)

OpenStudy (anonymous):

its a like we said

OpenStudy (anonymous):

awesome, thanks demo :)

OpenStudy (anonymous):

^_^

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