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find the inverse of the function F(x)= 1/6x+7
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\(\bf f(x)=\color{red}{y}= \cfrac{1}{6x}+7\qquad inverse\implies x=\cfrac{1}{6\color{red}{y}}+7\) notice to find the inverse function, all you do is swap the variables about then solve for "y"
all you do is switch x and y and since f(x) is basically y you would have x=1/6y+7. then you have to bring the 7 over to the other side and you would get x-7=1/6y. divide by 1/to get y by itself so the answer would be y=6x-42
divide by 1/6 *
i got it :)
thank you :)
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