Question

Solve the system of equations below.

5x-2y=18
3x+3y=15

???

Answer 1

online classes aha

Answer 2

let's try solving it using elimination
eliminate the variable y by multiplying the first equation by 3
and the second equation by 2.. then add both the new equations and tell me what you get..

Answer 3

\[5x-2y=18\]
\[3x+3y=15\]
\[\frac{3}{3}x+\frac{3}{3}=\frac{15}{3}\]
\[x+y=5\]
\[x=5-y\]
\[5(5-y)-2y=18\]
\[25-5y-2y=18\]
\[-7y=18-25\]
\[-7y=-7\]
\[y=1\]
\[x=4\]

Answer 4

5x - 2y = 18 --->(3)
3x + 3y = 15 -->(2)
-----------------
15x - 6y = 54 -- result of multiplying by 3
6x + 6y = 30 -- result of multiplying by 2
----------------add
21x = 84
x = 4

now sub 4 in for x in either of the original equations
5x - 2y = 18
5(4) - 2y = 18
20 - 2y = 18
-2y = 18 - 20
-2y = -2
y = 1

mattpyne is correct....x = 4 and y = 1

Answer 5

thank you !!!

Answer 6

glad to help :)