a chemist needs to make 3o ounces of a 30% alcohol solution by mixing a 15% alcohol solution with a 40% alcohol solution. how many ounces of the 40% solution does she need
We don't know how many ounces of solution are in the 15% alcohol solution or the 40% alcohol solution, but we do know that after mixing, there will be 30 ounces of solution so we can create this equation to represent the situation x + y = 30 where x = amount of ounces in the 15% solution y = amount of ounces in the 40% solution
so like 10 and 20?
Hang on...we can't just guess the amounts.
Whatever amount of x ounces is in the first solution, 15% of it will be alcohol. Whatever amount of y ounces in the second solution, 40% of it will be alcohol. After combining the amounts there will be 30% of 30 ounces of solution. We can represent this by the following equation .15x + .40y = .30(30)
So we can setup and solve this system of equations: x + y = 30 .15x + .40y = 9
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