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Precalculus 19 Online
OpenStudy (anonymous):

sinθ if cscθ= -2

OpenStudy (anonymous):

well what do you know about those 2 functions in relation to each other

OpenStudy (anonymous):

That's all it says on my homework paper, 'Use the appropriate reciprocal identity to find each function value.'

OpenStudy (anonymous):

ya, but you didn't answer my question. you have soh cah toa. and the three inverse functions. which one is the inverse of sin

OpenStudy (anonymous):

or maybe call it reciprocal? im not good at my language

OpenStudy (anonymous):

As far as I know it's reciprocal is csc=1/sin

OpenStudy (anonymous):

alright then. what do you think the answer is

OpenStudy (anonymous):

something like -1/2.

OpenStudy (anonymous):

I just have different ones like tanθ if cotθ=sqrt6/2 and I don't really understand

OpenStudy (anonymous):

so your correct on this problem. do you know about radians yet for the other problems?

OpenStudy (anonymous):

WHat do you mean radians?

OpenStudy (anonymous):

and cot and tan are reciprocals as well. radians-degrees. have you now done the unit circle yet?

OpenStudy (anonymous):

I don't recall so I am going to have to say no.

OpenStudy (anonymous):

well. hmm.. you need to learn about radians and degrees for trigonometry. but just to avoid that. remember that cot and tan are reciprocal identities as well. but you cant have a radical in the denominator

OpenStudy (anonymous):

Yea, so how would I go on in doing that? I am in Pre-cal if that makes a difference.

OpenStudy (anonymous):

http://tutorial.math.lamar.edu/cheat_table.aspx print that off. it will do wonders for your trig identities. do you know how to rationalize the denominator

OpenStudy (anonymous):

tell me where you are at on the second problem

OpenStudy (anonymous):

All I can really understand is that tanθ= 1/sqrt6/2, but I don't know how to make it like without the sqrt in the denominator.

OpenStudy (anonymous):

hm. what is the reciprocal of \[\frac{ \sqrt{6} }{ 2 }\]

OpenStudy (anonymous):

Umm tbh I'm not really sure :/

OpenStudy (anonymous):

You multiply the numerator and denominator by your square rooted number to get rid of the root in the bottom, this is known as rationalizing it. Here is an example |dw:1385354774715:dw|

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