solve 2/x-1 + 4/x = 8/x(x-1)
x(2/x-1+4/x=x(8/x)(x-1) 2-x+4=8x-8 14=7x x=2
can you explain please
\[\frac{ 2 }{ x-1 }+\frac{ 4 }{ x }=\frac{ 8 }{ x(x+1) }\] like this?
yes like that
\[(\frac{ 2 }{ x-1 }+\frac{ 4 }{ x }=\frac{ 8 }{ (x)(x-1) })x(x-1)\] like @spiel7 said but it come out a little different then he said
what do you get when you do this?
i saw the equation incorrectly. big teach has the ball. find the lcd and you are home
sorry i dont really get it
common lcd is x(x+1)(x-1)
once you do these it will get rid of all the fractions and you will be able to solve the normal way all we are doing is multippling by all the denomenators
there isn't an x+1 denominator, it's x-1
sorry i missed typed the first ime then. So do not multiply by the x+1 just x and x-1 this will make it a lot easier :)
yyou should get \[2x+4(x-1)=8\] do you see how?
yea i get it
cool sorry about the confusion!! :) So get how to finish the equation
so 2x+ 4x-4=8 move over the 8 then factor
there are no x^2 in here so no factor easy solve
6x-4=8
oh yea yea i dont factor, ok yea sorry got it
np
thanks
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