Question

if p(A)=p(B)=.15, p(C)=.4, and p(D)=2p(E). find the probs of D and E

Answer 1

are we to assume that they all add up to 1?

Answer 2

yes

Answer 3

if so, then the ration of D to E is 1 to 2

1 - A - B - C gives us what is left to divvy up

dividing that by 3 allows us to sort it by a ration of 1 to 2. D=1/3 E = 2/3

does that make sense?

Answer 4

not really

Answer 5

if they all add to one we have:

A+B+C+D+E = 1

A+B+C+D+2D = 1

A+B+C+3D = 1

3D = 1-A-B-C

D = (1-A-B-C)/3

Answer 6

ok

Answer 7

D is 1/3 of whats left .. therefore E is 2/3 of whats left

Answer 8

i just checked the back of the text book and it says D=.20, E=.10

Answer 9

yes, that would be what we get. i mighta seen the E,D parts a little backwards tho :)

Answer 10

more explanation pls

Answer 11

ive really explaned it as much as i can ... i need to know what you are seeing it as.

Answer 12

all this is is adding parts to equal 1

Answer 13

they give you the value of most of the parts, and a relationship between the 2 unknowns

Answer 14

tx alot. i,m so grateful