Question

find the derivative of f(x)= x(x^2-1) / (x+3). Simplify your answer

Answer 1

i think quotient rule here

f = x^3 - x f' = 3x^2 - 1
g = x+3 g' = 1

\[(\frac{f}{g})' = \frac{f'g - fg'}{g^{2}}\]

Answer 2

so that would be 3x^2-1(x+3) / 1^2

Answer 3

what would I do from there?

Answer 4

@dumbcow

Answer 5

because wolframalpha says the derivative is f'(x) = 2x^3+9x^2-3 / (x+3 )^2 but I dont know how it got to thtat

Answer 6

please help me?

Answer 7

@dumbcow