Question

use a net to find the surface area

Answer 1

'to use a net' is like wrapping the object in a net? so, finding the area of each surface indivualy?

Answer 2

here are the measurements of the first prism.
19, 6.5, 29
how many sides will have the dimensions of 19 times 6.5?

Answer 3

2

Answer 4

correct ^_^
so for the area we have so far:
A = 2*( 19*6.5) + ? + ?

how many sides have the dimensions: 19 times 29?

Answer 5

2

Answer 6

ok so basically
A=188.5(2)+551(2)+123.5(2)
A=1726

Answer 7

right again.
A = 2*( 19*6.5) + 2*(19*29) + ?
and you can tell that the last sides are the 6.5*29, and there are two sides of them
A = 2*( 19*6.5) + 2*(19*29) + 2*(6.5*29)

now, can you try doing the same thing we did but on the other two objects

Answer 8

yep, ^_^
good work

Answer 9

thanks for explaining @DemolisionWolf

Answer 10

^_^

Answer 11

i'll check your answers for the last two prisms if you would like

Answer 12

i only have to do odd ones lol
and i appreciate it

Answer 13

ok so how do i do it with a triangle

Answer 14

ok!
so on #9, you'll need to use the equation for the area of a triangle = (1/2)*base*height. and you'll need to use the pathagorean equation of a^2 + b^2 = c^2 when finding the dimensions for the side that is sloped like a slide

Answer 15

ok so lets see 1/2(4*4) =8

Answer 16

am i on the right track

Answer 17

yep ^_^

Answer 18

did you get an answer yet or need some help? ^_^

Answer 19

not yet i still need help

Answer 20

im super lost on this one

Answer 21

so we have a triangle: (1/2)*4*4
and we have two of them so,
2* (1/2)4*4

and we have 3 rectangles, two are the same, and one is different
the two that are the same are the 4*8
since we have 2 we will do
2*(4*8)

now the trick part is getting the rectangle that is sloped like a slide. it has a lenght of 8 but the other side length is too hard to tell.

but is everything making sense so far?

Answer 22

yes so far

Answer 23

so how do i find the sloped side

Answer 24

we find the sloped side by using pathagorean's therom.
its like this:
a^2 + b^2 = c^2
or
c = sqrt(a^2 + b^2)

do you see how a is like 4
and b is like 4
and c is like x?

Answer 25

i cant see the drawing for some reason

Answer 26

but i understand

Answer 27

ok ^_^
so we need to solve for the sloped lenght of the that triangle.
and the sloped lenght we are going to call C,
C = sqrt (4^2 + 4^2)
solve for C

Answer 28

\[C=\sqrt(4^2+4^2)\]
\[C=\sqrt 32\]
\[C= 4\sqrt2\]

Answer 29

ok so what now

Answer 30

so now we have the length of that sloped edge of 4sqrt(2), so now we can find it's area, which would be
4sqrt(2) * 8

so now we have all the areas of the sides:
Area = 2* (1/2)4*4 + 2*(4*8) + 4sqrt(2) * 8

Answer 31

45.2548339959 is what i got for 4sqrt2*8

Answer 32

45.25 is good enough ^_^

Answer 33

ok
16+64+45.25=A

Answer 34

is that how it is supposed to look?

Answer 35

=125.25 ? ya?

Answer 36

yea

Answer 37

good work ^_^

Answer 38

but in my book it says it is 125.3 units^2

Answer 39

oh teehee i see

Answer 40

ty again @demolisionwolf

Answer 41

125.25 rounded up becomes 125.3
^_^