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Mathematics 13 Online
OpenStudy (anonymous):

calculus help......picture below

OpenStudy (anonymous):

OpenStudy (anonymous):

answer is 110 but idk how

OpenStudy (agent0smith):

You'll need to find the area under that curve first, since f(x) is the integral of f'

OpenStudy (anonymous):

how can i find the area?

OpenStudy (dumbcow):

ok f(x) is at max when f'(x) = 0 thus at x=6 because f'(6) = 0 use the "y-values" of the points on graph at (2,16) (4,32) (5,25) to estimate how f(x) is increasing in each interval given: f(2) = 10 , at x=2 slope = 16 so f(4) = 10+2*16 = 42 (note this is a low estimate since slope is increasing) at x = 4 slope = 32 f(5) = 42 + 32 = 74 x=5 slope = 25 f(6) = 74 + 25 = 99

OpenStudy (dumbcow):

prob should have used point (3,26) to get estimate closer to 110

OpenStudy (anonymous):

I dont understand:/

OpenStudy (agent0smith):

Find the area under the curve between x=0 and 6. Count the number of squares (approximately)

OpenStudy (anonymous):

but how will end up being 110?

OpenStudy (agent0smith):

Find the area under the curve first, count the squares, and figure out what the area of one square is. Then we'll deal with the f(2) = 10 (it doesn't really have much impact here... the area between x=0 and 2 is about 15 anyway)

OpenStudy (anonymous):

oh okay i got it thanks

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