calculus help......picture below
answer is 110 but idk how
You'll need to find the area under that curve first, since f(x) is the integral of f'
how can i find the area?
ok f(x) is at max when f'(x) = 0 thus at x=6 because f'(6) = 0 use the "y-values" of the points on graph at (2,16) (4,32) (5,25) to estimate how f(x) is increasing in each interval given: f(2) = 10 , at x=2 slope = 16 so f(4) = 10+2*16 = 42 (note this is a low estimate since slope is increasing) at x = 4 slope = 32 f(5) = 42 + 32 = 74 x=5 slope = 25 f(6) = 74 + 25 = 99
prob should have used point (3,26) to get estimate closer to 110
I dont understand:/
Find the area under the curve between x=0 and 6. Count the number of squares (approximately)
but how will end up being 110?
Find the area under the curve first, count the squares, and figure out what the area of one square is. Then we'll deal with the f(2) = 10 (it doesn't really have much impact here... the area between x=0 and 2 is about 15 anyway)
oh okay i got it thanks
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