A stone is thrown straight up from the edge of a roof, 775 feet above the ground, at a speed of 18 feet per second.
Remembering that the acceleration due to gravity is -32ft/sec^2, how high is the stone 6 seconds later?
At what time does the stone hit the ground?
What is the velocity of the stone when it hits the ground?

Question

A stone is thrown straight up from the edge of a roof, 775 feet above the ground, at a speed of 18 feet per second. 
 Remembering that the acceleration due to gravity is  -32ft/sec^2, how high is the stone 6 seconds later? 
At what time does the stone hit the ground?
What is the velocity of the stone when it hits the ground?

anonymous · Answer

The equation for this is 1/2 at^2 +vt+x.  A is the acceleration, v is the velocity and x is the position.

anonymous · Answer

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